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SubjectRe: [PATCH] kernel: module: strncpy issue, using strlcpy instead of strncpy
On 2013年04月07日 22:28, Geert Uytterhoeven wrote:
> On Sun, Apr 7, 2013 at 1:38 PM, Chen Gang <gang.chen@asianux.com> wrote:
>> > ownername and namebuf are all NUL terminated string.
>> >
>> > need always let them ended by '\0'.
>> >
>> > Signed-off-by: Chen Gang <gang.chen@asianux.com>
>> > ---
>> > kernel/module.c | 4 ++--
>> > 1 files changed, 2 insertions(+), 2 deletions(-)
>> >
>> > diff --git a/kernel/module.c b/kernel/module.c
>> > index 3c2c72d..597efd8 100644
>> > --- a/kernel/module.c
>> > +++ b/kernel/module.c
>> > @@ -3464,7 +3464,7 @@ const char *module_address_lookup(unsigned long addr,
>> > }
>> > /* Make a copy in here where it's safe */
>> > if (ret) {
>> > - strncpy(namebuf, ret, KSYM_NAME_LEN - 1);
>> > + strlcpy(namebuf, ret, KSYM_NAME_LEN);
>> > ret = namebuf;
>> > }
>> > preempt_enable();
> Is this buffer ever copied to userspace?


at lease now:
I think, it is not, the reason is:
it is only a tool function for kallsyms using.
it has no duty to let namebuf initialized.

please reference the related comments in include/linux/module.h

493 /* For kallsyms to ask for address resolution. namebuf should be at
494 * least KSYM_NAME_LEN long: a pointer to namebuf is returned if
495 * found, otherwise NULL. */
496 const char *module_address_lookup(unsigned long addr,
497 unsigned long *symbolsize,
498 unsigned long *offset,
499 char **modname,
500 char *namebuf);


originally:
it will not cause issue (the upper caller has noticed it).
but we really need let it '\0' ended within module_address_lookup.
(so, maybe for subject: "strncpy issue" need be deleted)


in the future:
since it is an extern function, it can be used by others.
since it is a tool function, it can not be used directly by user mode.
according to the api definition:
if it is necessary to initialize (such as return to user mode)
the caller should perform it.
if it is not necessary to initialize (not return to user mode)
still prefer the caller to initialize it.
but should understand if the caller will not initialize it.
(if caller does not initialize it, it should not cause issue)


thanks.

:-)


--
Chen Gang

Asianux Corporation
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