Messages in this thread | | | Date | Thu, 07 Feb 2013 20:32:57 +0400 | From | Michael Tokarev <> | Subject | Transparent Huge Pages |
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Hello.
I'm trying to understand how to use transparent huge pages (currently in x86). Before I used "explicit" huge pages alot (mostly about hugetlbfs), but it looked like THP should be easier so I gave it a try.
This tiny program:
----- cut ----- #include <unistd.h> #include <stdio.h> #include <stdlib.h> #include <sys/types.h> #include <sys/mman.h> #include <errno.h> #include <string.h>
int main(int argc, char **argv) { void *ptr; size_t len = argv[1] ? atoi(argv[1]) : 1024*1024*1024; /* no error checking! */ posix_memalign(&ptr, 2048*1024, len); madvise(ptr, len, MADV_HUGEPAGE); memset(ptr, 0, len); usleep(500); /* let khugepagesd do its work */ system("grep ^AnonHugePages: /proc/meminfo"); return 0; } ----- cut -----
which just tries to allocate some amount of RAM (1Gb by default) aligned to 2Mb, uses madvise(HUGEPAGE) on it, and checks /proc/meminfo for AnonHugePages.
The problem is: I've never seen any value for AnonHugePages larger than about 16Mb. Usually it is around 10Mb or 8Mb, no matter how large the requested memory size is, including the default 1Gb.
The question, obviously, is: why so small?
My system (which is a few years old now) has 6Gb of RAM, it uses AMD Athlon II X2 260 CPU, and is running 3.2 kernel.
Original question comes from grounds of of QEMU, which is supposed to use THP for guest memory, but it also does not use more than these ~10Mb, when allocating 1Gb to the guest.
Thanks!
/mjt
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