Messages in this thread | | | Date | Thu, 15 Mar 2001 16:16:10 +0300 | From | Art Boulatov <> | Subject | pivot_root & linuxrc problem |
| |
Hi,
may be thats a bug, or I'm doing something really wrong :)
from Documentation/initrd.txt:
"# cd /new-root # mkdir initrd # pivot_root . initrd
Now, the linuxrc process may still access the old root via its executable, shared libraries, standard input/output/error, and its current root directory. All these references are dropped by the following command:
# exec chroot . what-follows <dev/console >dev/console 2>&1
Where what-follows is a program under the new root, e.g. /sbin/init"
How can I "exec /sbin/init" from "/linuxrc", whatever it is, if "linuxrc" does not get PID=1?
Actually, why does NOT "linuxrc" get PID=1?
A task list after booting with "root=/dev/rd/0" and "init=/linuxurc", where "linuxrc" is simply "bash", shows that: "swapper" got PID=1, next come other kernel threads with a parent PID=1, and "linuxrc" got PID=7 and a parent PID=1.
"init" sees it does not have PID=1 and simply bails out, next happens this:
"Note: if linuxrc or any program exec'ed from it terminates for some reason, the old change_root mechanism is invoked (see section "Obsolete root change mechanism")."
I probably misunderstand something here, but could you please help?
In summary:
What is "swapper" and why does it get PID=1 and "linuxrc" does not? If it is supposed to be that way, how do I "exec /sbin/init" from "linuxrc" then? Also why "/linuxrc" is hardcoded in init/main.c, so telling kernel "root=/dev/rd/0 init=/sbin/whatever" does still invoke "/linuxrc"?
Thanks a lot, Art.
- To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
| |