Messages in this thread | | | Date | Fri, 29 Sep 2023 13:45:07 +0200 | Subject | Re: [PATCH v2 4/7] thermal: exynos: simplify regulator (de)initialization | From | Daniel Lezcano <> |
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On 29/09/2023 13:03, Marek Szyprowski wrote: > On 29.09.2023 12:46, Daniel Lezcano wrote: >> On 26/09/2023 13:02, Mateusz Majewski wrote: >>> Hi, >>> >>>> This is not equivalent. If regulator is provided and enable fails, the >>>> old code is nicely returning error. Now, it will print misleading >>>> message - failed to get regulator - and continue. >>>> >>>> While this simplifies the code, it ignores important running >>>> condition - >>>> having regulator enabled. >>> >>> Would doing this be correct? >>> >>> ret = devm_regulator_get_enable_optional(&pdev->dev, "vtmu"); >>> switch (ret) { >>> case 0: >>> case -ENODEV: >> >> Not sure to understand why -NODEV is not an error > > > Because this what devm_regulator_get_enable_optional() returns if no > regulator is defined. I also got confused by this a few times.
The code before this change calls devm_regulator_get_optional() which returns -ENODEV too, right ? But there is no special case for this error.
So this change uses devm_regulator_get_enable_optional() and handle the ENODEV as a non-error, so there is a change in the behavior.
>>> break; >>> case -EPROBE_DEFER: >>> return -EPROBE_DEFER; >>> default: >>> dev_err(&pdev->dev, "Failed to get enabled regulator: %d\n", >>> ret); >>> return ret; >>> } >> >> ret = devm_regulator_get_enable_optional(&pdev->dev, "vtmu"); >> if (ret < 0) { >> if (ret != EPROBE_DEFER) >> dev_err(&pdev->dev, "Failed to get enabled regulator: %d\n", >> ret); >> return ret; >> } >> >> ?? >> > Best regards
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