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SubjectRe:Re: Re: [PATCH] input/serio: Fix refcount leak bug in i8042-sparcio




At 2022-07-11 11:19:20, "Dmitry Torokhov" <dmitry.torokhov@gmail.com> wrote:
>On Sun, Jul 10, 2022 at 09:37:10AM +0800, Liang He wrote:
>> At 2022-07-09 12:49:23, "Dmitry Torokhov" <dmitry.torokhov@gmail.com> wrote:
>> >Hi Liang,
>> >
>> >On Sun, Jun 19, 2022 at 03:30:36PM +0800, Liang He wrote:
>> >> In i8042_platform_init() and i8042_platform_exit(), we need call
>> >> of_node_put() to keep refcount balance.
>> >>
>> >> Signed-off-by: Liang He <windhl@126.com>
>> >> ---
>> >> drivers/input/serio/i8042-sparcio.h | 4 ++++
>> >> 1 file changed, 4 insertions(+)
>> >>
>> >> diff --git a/drivers/input/serio/i8042-sparcio.h b/drivers/input/serio/i8042-sparcio.h
>> >> index fce76812843b..a2a9db9220d7 100644
>> >> --- a/drivers/input/serio/i8042-sparcio.h
>> >> +++ b/drivers/input/serio/i8042-sparcio.h
>> >> @@ -108,6 +108,8 @@ static int __init i8042_platform_init(void)
>> >> struct device_node *root = of_find_node_by_path("/");
>> >> const char *name = of_get_property(root, "name", NULL);
>> >>
>> >> + of_node_put(root);
>> >> +
>> >> if (name && !strcmp(name, "SUNW,JavaStation-1")) {
>> >> /* Hardcoded values for MrCoffee. */
>> >> i8042_kbd_irq = i8042_aux_irq = 13 | 0x20;
>> >> @@ -139,6 +141,8 @@ static inline void i8042_platform_exit(void)
>> >> struct device_node *root = of_find_node_by_path("/");
>> >> const char *name = of_get_property(root, "name", NULL);
>> >>
>> >> + of_node_put(root);
>> >> +
>> >> if (!name || strcmp(name, "SUNW,JavaStation-1"))
>> >> platform_driver_unregister(&sparc_i8042_driver);
>> >> }
>> >
>> >There already was an attempt to fix this issue in a slightly better way,
>> >unfortunately the original author did not finish the work:
>> >
>> >https://lore.kernel.org/all/20181212163548.23723-1-tiny.windzz@gmail.com/
>> >
>> >Thanks.
>> >
>> >--
>> >Dmitry
>>
>> Hi, Dmirtry,
>>
>> Thanks for reviewing my patch code.
>>
>> The Li's patch adds a helper and is better than mine.
>
>Right, however there is a compile error in Li's version. It would be
>great if someone could finish their work.
>
>Thanks.
>
>--
>Dmitry


Thanks,

I'd like to continue Li's work and complete it soon.

Liang
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