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SubjectRe: fix int_sqrt() for very large numbers
On Sun, 20 Jan 2019 at 09:31, Crt Mori <cmo@melexis.com> wrote:
>
> On Sun, 20 Jan 2019 at 04:49, Linus Torvalds
> <torvalds@linux-foundation.org> wrote:
> >
> > On Sun, Jan 20, 2019 at 12:01 PM Will Deacon <will.deacon@arm.com> wrote:
> > >
> > > > @@ -52,7 +52,7 @@ u32 int_sqrt64(u64 x)
> > > > if (x <= ULONG_MAX)
> > > > return int_sqrt((unsigned long) x);
> > > >
> > > > - m = 1ULL << (fls64(x) & ~1ULL);
> > > > + m = 1ULL << ((fls64(x) - 1) & ~1ULL);
> > >
> > > This just looks like a copy-paste error because there isn't an __fls64().
> > > But I think your suggestion here is ok, given the previous check against
> > > ULONG_MAX.
> >
> > Hmm. We probably *should* add a __fls64().
> >
> > There looks to be only one user of int_sqrt64(), and that one is
> > confused. It does int_sqrt64() twice, but since the inner one will
> > reduce the range to 32 bits, the outer one is just silly.
>
> II have a usecase (mlx90632) where this calculation worked on arm64
> (nexus), but not in normal 32-bit arm (beaglebone). I have tried going
> with full u64 to u64, but I was persuaded that it is not necessary and
> testing on black body (sensor range from 0 - 80 degrees) confirmed
> that for my calculations u32/u64 is enough. Because of the testing

I have just re-read the patch submit discussion and a sqrt of 64bit
number can never be more than 32bit. That is why u32 return value is
enough. But I do not clearly remember if I tested with outside
int_sqrt (insted int_sqrt64). We still have everything, so I could
test if that is the suggestion.

> range (and keep in mind it is casted to signed after two sqrts) the
> high bit might never affect my end result, but I needed precision, not
> the range. Inside the function the b was 32bit on 32bit core, but I
> needed it to be 64bit. To keep it similar to existing int_sqrt, I have
> decided to just type all variables there to 64bit.
>
> We have implementation of this with doubles (see datasheet) and I
> ported it to integer on arm64. The end result was fairly similar
> calculation (for within object tempearture range from 0-80), between
> both.
>
> > That one user also had better not be overflowing into the high bit -
> > it uses "s64" as a type and does seem to use signed operatons, so high
> > bit set really means negative. sqrt() returning something odd for a
> > negative number wouldn't be all that odd in that context.
> >
> > But yes, our current int_sqrt64() does seem buggy as-is, because it's
> > *supposed* to work on u64's, even if I don't think we really have any
> > users that care.
>
> I introduced strong types for existing int_sqrt implementation to keep
> it aligned between 64bit and 32bit.
>
> Best regards,
> Crt
>
> > And as Will mentioned, the regular int_sqrt() looks perfectly fine,
> > and subtracting 1 from the __fls() return value would actually
> > _introduce_ a bug.
> >
> > Linus

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