Messages in this thread | | | Date | Tue, 26 Jun 2018 08:38:22 -0300 | From | Henrique de Moraes Holschuh <> | Subject | Re: [PATCH] x86-64: use 32-bit XOR to zero registers |
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On Tue, 26 Jun 2018, Jan Beulich wrote: > >>> On 25.06.18 at 18:33, <rdunlap@infradead.org> wrote: > > On 06/25/2018 03:25 AM, Jan Beulich wrote: > >> Some Intel CPUs don't recognize 64-bit XORs as zeroing idioms - use > >> 32-bit ones instead. > > > > Hmph. Is that considered a bug (errata)? > > No. > > > URL/references? > > Intel's Optimization Reference Manual says so (in rev 040 this is in section > 16.2.2.5 "Zeroing Idioms" as a subsection of the Goldmont/Silvermont > descriptions). > > > Are these changes really only zeroing the lower 32 bits of the register? > > and that's all that the code cares about? > > No - like all operations targeting a 32-bit register, the result is zero > extended to the entire 64-bit destination register.
Missing information that would have been helpful in the commit message:
When the processor can recognize something as a zeroing idiom, it optimizes that operation on the front-end. Only 32-bit XOR r,r is documented as a zeroing idiom according to the Intel optimization manual. While a few Intel processors recognize the 64-bit version of XOR r,r as a zeroing idiom, many won't.
Note that the 32-bit operation extends to the high part of the 64-bit register, so it will zero the entire 64-bit register. The 32-bit instruction is also one byte shorter.
The last sentence is just a reminder, for completeness...
-- Henrique Holschuh
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