Messages in this thread | | | Subject | Re: Bug 71331 - mlock yields processor to lower priority process | From | Oliver Neukum <> | Date | Fri, 21 Mar 2014 14:35:25 +0100 |
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On Fri, 2014-03-21 at 12:18 +0000, jimmie.davis@l-3com.com wrote: > > >How is that different from any other time a task has to yield the CPU > >for a bit? While your high priority task is blocked for whatever > >reason, a lower priority task gets to use the CPU. > > > As the submitter of the bug, let me give you my perspective. SCHED_FIFO means run my task until it blocks or a higher priority task pre-empts it. Period. > > mlock() doesn't block. check the man page.
It guarantees that all pages be in RAM. That means it has to read them in if they aren't. How could it do that without blocking?
Regards Oliver
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