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    Subject[PATCH 3.16 027/357] of: Allow mem_reserve of memory with a base address of zero
    Date
    3.16-stable review patch.  If anyone has any objections, please let me know.

    ------------------

    From: Al Cooper <alcooperx@gmail.com>

    commit b5f2a8c02697c3685ccbbb66495465742ffa0dc1 upstream.

    __reserved_mem_reserve_reg() won't reserve memory if the base address
    is zero. This change removes the check for a base address of zero and
    allows it to be reserved.

    Allowing the first 4K of memory to be reserved will help solve a
    problem on some ARM systems where the the first 16K of memory is
    unused and becomes allocable memory. This will prevent this memory
    from being used for DMA by drivers like the USB OHCI driver which
    consider a physical address of zero to be illegal.

    Signed-off-by: Al Cooper <alcooperx@gmail.com>
    Signed-off-by: Grant Likely <grant.likely@linaro.org>
    Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>

    ---
    drivers/of/fdt.c | 2 +-
    1 file changed, 1 insertion(+), 1 deletion(-)

    --- a/drivers/of/fdt.c
    +++ b/drivers/of/fdt.c
    @@ -453,7 +453,7 @@ static int __init __reserved_mem_reserve
    base = dt_mem_next_cell(dt_root_addr_cells, &prop);
    size = dt_mem_next_cell(dt_root_size_cells, &prop);

    - if (base && size &&
    + if (size &&
    early_init_dt_reserve_memory_arch(base, size, nomap) == 0)
    pr_debug("Reserved memory: reserved region for node '%s': base %pa, size %ld MiB\n",
    uname, &base, (unsigned long)size / SZ_1M);



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