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SubjectRe: [PATCH 01/11] irqchip: Allow irq_reg_{readl,writel} to use __raw_{readl_writel}
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On Wednesday 29 October 2014 13:09:47 Kevin Cernekee wrote:
> On Wed, Oct 29, 2014 at 12:14 PM, Arnd Bergmann <arnd@arndb.de> wrote:
> >> The host CPU is connected to the peripheral/register interface using a
> >> 32-bit wide data bus. A simple 32-bit store originating from the host
> >> CPU, targeted to an onchip SoC peripheral, will never need endian
> >> swapping. i.e. this code works equally well on all supported systems
> >> regardless of endianness:
> >>
> >> volatile u32 *foo = (void *)MY_REG_VA;
> >> *foo = 0x12345678;
> >>
> >> 8-bit and 16-bit accesses may be another story, but only appear in a
> >> few very special peripherals.
> >
> > Sorry, but this makes no sense. If you run a little-endian kernel
> > on one of the MIPS systems that you marked as "always BE", or a
> > big-endian kernel on the systems that are marked "always LE",
> > then you have to byte swap.
>
> If I ran an LE MIPS kernel on a BE system, it would hang on boot. I
> know this through experience.

What is a "BE system" then? Is the CPU core not capable of running
code either way?

> Setting aside the problem that the instruction words, pointers, and
> bitfields in the image are all in the wrong byte order, there are many
> other endian-specific assumptions baked into the executable.

Most of those are handled by the compiler. Bitfields are of course
a problem when they are accessed through DMA, but I would assume
that this is still a problem with the hardware byteswap hack that
the Broadcom SoCs have.

Of course, anything that uses __raw_readl on an MMIO register is
broken if you try to do this, which was my point the whole time.

> Does this actually work on other architectures like ARM? I still see
> compile-time checks for CONFIG_CPU_ENDIAN* in a couple of places under
> arch/arm.

Yes, it should work on any architecture that supports both modes. It
definitely works on all ARM cores I know, and on most PowerPC cores.
I always assumed that MIPS was bi-endian as well, but according to
what you say I guess it is not.

ARM and PowerPC can actually switch endianess in the kernel, and this
is what they do in the first instruction when you run a different
endianess from what the boot loader runs as it calls into the kernel.
The ARM boot protocol requires entering the kernel in little-endian
mode, while I think on PowerPC the boot loader is supposed to detect
the format of the kernel binary and pick the right mode before calling
it.

> >> Or, we could add IRQ_GC_NATIVE_IO and/or IRQ_GC_BE_IO to enum irq_gc_flags.
> >>
> >> Would either of these choices satisfy everyone's goals?
> >
> > This is what I meant with doing extra work in the case where we want to
> > support both in the same kernel. We would only enable the runtime
> > logic if both GENERIC_IRQ_CHIP and GENERIC_IRQ_CHIP_BE are set, and
> > leave it up to the platform to select the right one. For MIPS BCM7xxx,
> > you could use
> >
> > config BCM7xxx
> > select GENERIC_IRQ_CHIP if CPU_LITTLE_ENDIAN
> > select GENERIC_IRQ_CHIP_BE if CPU_BIG_ENDIAN
> >
> > so you would default to the hardwired big-endian accessor unless
> > some other drivers selects GENERIC_IRQ_CHIP.
>
> generic-chip.c already has a fair amount of indirection, with pointers
> to saved masks, user-specified register offsets, and such. Is there a
> concern that introducing, say, a pair of readl/writel function
> pointers, would cause an unacceptable performance drop?

I don't know. Thomas' reply suggests that it isn't. Doing byteswap
in software at a register access is usually free in terms of CPU
cycles, but an indirect function call can be noticeable if we do
that a lot.

> Backing up a little bit, do we have a consensus that defining
> irq_reg_{readl,writel} at compile time from include/linux/irq.h is a
> bad idea for multiplatform images, and it should be removed one way or
> another?

If we can prove at compile-time that all users of irq_reg_{readl,writel}
are the same, then I think it's ok to hardcode it, but of course if
any driver we build needs the opposite of the others, or needs CPU-endian
access, then it definitely can't work.

Arnd


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