Messages in this thread |  | | Date | Mon, 30 Dec 2013 19:06:00 +0100 | From | Oleg Nesterov <> | Subject | Re: [PATCH 4/5] audit: anchor all pid references in the initial pid namespace |
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On 12/23, Richard Guy Briggs wrote: > > Store and log all PIDs with reference to the initial PID namespace and > use the access functions task_pid_nr() and task_tgid_nr() for task->pid > and task->tgid rather than access them directly.
At first glance this patch looks like a good cleanup, but...
> @@ -429,6 +429,19 @@ static struct audit_entry *audit_data_to_entry(struct audit_rule_data *data, > f->val = 0; > } > > + if ((f->type == AUDIT_PID) || (f->type == AUDIT_PPID)) { > + struct pid *pid; > + rcu_read_lock(); > + pid = find_vpid(f->val); > + if (!pid) { > + rcu_read_unlock(); > + err = -ESRCH; > + goto exit_free; > + } > + f->val = pid_nr(pid); > + rcu_read_unlock(); > + }
I do not really understand this change, but this doesn't matter, I do not understand audit.
However, I think this deserves a separate patch with the changelog.
> @@ -278,9 +278,12 @@ static void dump_common_audit_data(struct audit_buffer *ab, > } > case LSM_AUDIT_DATA_TASK: > tsk = a->u.tsk; > - if (tsk && tsk->pid) { > - audit_log_format(ab, " pid=%d comm=", tsk->pid); > - audit_log_untrustedstring(ab, tsk->comm); > + if (tsk) { > + pid_t pid = task_pid_nr(tsk); > + if (pid) { > + audit_log_format(ab, " pid=%d comm=", pid); > + audit_log_untrustedstring(ab, tsk->comm);
Just curious, is it really possible that a->u.tsk is an idle thread?
Oleg.
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