Messages in this thread | | | Date | Tue, 12 Nov 2013 15:05:43 +0800 | From | Hongbo Zhang <> | Subject | Re: [PATCH v11 3/3] DMA: Freescale: update driver to support 8-channel DMA engine |
| |
On 11/12/2013 08:09 AM, Dan Williams wrote: > On Mon, Nov 11, 2013 at 1:12 AM, Hongbo Zhang > <hongbo.zhang@freescale.com> wrote: >>>>>> diff --git a/drivers/dma/fsldma.c b/drivers/dma/fsldma.c >>>>>> index 49e8fbd..16a9a48 100644 >>>>>> --- a/drivers/dma/fsldma.c >>>>>> +++ b/drivers/dma/fsldma.c >>>>>> @@ -1261,7 +1261,9 @@ static int fsl_dma_chan_probe(struct >>>>>> fsldma_device >>>>>> *fdev, >>>>>> WARN_ON(fdev->feature != chan->feature); >>>>>> chan->dev = fdev->dev; >>>>>> - chan->id = ((res.start - 0x100) & 0xfff) >> 7; >>>>>> + chan->id = (res.start & 0xfff) < 0x300 ? >>>>>> + ((res.start - 0x100) & 0xfff) >> 7 : >>>>>> + ((res.start - 0x200) & 0xfff) >> 7; >>>>>> if (chan->id >= FSL_DMA_MAX_CHANS_PER_DEVICE) { >>> Isn't it a bit fragile to have this based on the resource address? >>> Can't device tree tell you the channel id directly by an index into >>> the "dma0: dma@100300" node? >> >> Yes, both this way and putting a "cell-index" into device tree work. >> This won't be fragile, because the resource address should always be defined >> correctly, otherwise even if we can tell a channel id by "cell-index" but >> with wrong resource address, nothing will work. >> This piece of code only doesn't seem as neat as using "cell-index", but we >> prefer the style that let the device tree describes as true as what hardware >> really has. This doesn't mean "cell-index" isn't acceptable, if it is >> necessary and unavoidable, we can send another patch to add it, but >> currently there is no need and we don't have to do this. >> > I'm pointing it out because we just had a bug fix to another driver > motivated by the fact that resource addresses may move from one > implementation to another, whereas the cell index provided by device > tree is static. Just a note, no need to fix it now.
Get it, and will remember it, thank you Dan. > -- > Dan >
| |