On Tue, 2011-12-13 at 21:00 +0100, Peter Zijlstra wrote: > On Mon, 2011-12-12 at 10:02 -0800, Dmitry Torokhov wrote: > > 1 is a power of two, therefore rounddown_pow_of_two(1) should return 1. > > x^0 = 1 > x^1 = x > > Seems to me 0 was the right answer, no?
n/m head-up-arse, missed that this wasn't actually a log variant.