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SubjectRe: Make yield_task_fair more efficient
On Thu, Feb 21 2008, Jens Axboe wrote:
> On Thu, Feb 21 2008, Peter Zijlstra wrote:
> >
> > On Thu, 2008-02-21 at 15:37 +0530, Balbir Singh wrote:
> >
> > > You use the empty pointer (missing right child), so why do we need a list. May
> > > be I am missing something.
> >
> > A fully threaded tree also has back-pointer to traverse backwards
> > through the ordered elements.
> >
> > That said, overloading the right child pointer might not be the best
> > thing for the linux kernel, as it will impact all the rb-tree lookups
> > which are open-coded and often performance critical (this is the reason
> > the colour isn't bit encoded in either of the child pointers either).
> >
> > But if you only want a uni directional thread, I guess we can stick it
> > in the unsigned long we use for the node colour.
> >
> > Still, perhaps it's worth it to grow rb_node to 4 words and do the fully
> > threaded thing as there are also a lot of rb_prev() users in the kernel.
> > Who knows..
> >
> > Anyway, I agree that improving rb_next() is worth looking into for the
> > scheduler.
>
> For the IO scheduler as well, it's used quite extensively! So speeding
> up rb_next() would definitely help, as it's typically invoked for every
> bio queued (attempting to back merge with the next request). CFQ and AS
> additionally does an rb_next() and rb_prev() when trying to decide which
> request to do next.

One possible course of action to implement this without eating extra
space in the rb_node would be:

- Add rb_right() and rb_set_right() (plus ditto _left variants) to
rbtree.h
- Convert all in-kernel users to use these. Quite extensive, as the
rbtree code search/insert functions are coded in situ and not in
rbtree.[ch]
- Now we can overload bit 0 of ->rb_right and ->rb_left to indicate
whether this is a node or thread pointer and modify rbtree.c to tag
and add the thread links when appropriate.

So we can definitely do this in a compatible fashion. Given that I have
a flight coming up in a few days time, I may give it a got if no one
beats me to it :-)

--
Jens Axboe



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