Messages in this thread | | | Date | Tue, 20 Sep 2005 17:20:03 +0200 | From | Peter Duellings <> | Subject | Re: kernel error in system call accept() under kernel 2.6.8 |
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Hi Ben,
if Log.Log would modify errno the Log.Log debug output should not be affected since the value of errno - from my understanding - is copied on the stack *before* Log.Log is called. Or did I forget something?
Thanx,
Peter
Benjamin LaHaise wrote: > On Tue, Sep 20, 2005 at 04:25:08PM +0200, Peter Duellings wrote: > >>//accept may return with a protocol error, simply try again >>while( (n = accept(m_ListenFd, (struct sockaddr *) cliaddr, &len)) < 0) >>{ >> Log.Log("Error accept, fd=%d, addrlen=%d, len=%d, errno=%d, %s", >>m_ListenFd, >>m_AddrLen, len, errno, strerror_r(errno, l_strebuf, sizeof(l_strebuf))); >> if (errno == EPROTO || errno == ECONNABORTED) //connection already > > > Let's see here: what happens if Log.Log() performs a syscall to, say, > write out the log message to a buffer? > > -ben
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