Messages in this thread | | | Date | Sun, 24 Jul 2005 21:41:49 +0200 | From | Brice Goglin <> | Subject | Re: kernel 2.6 speed |
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Le 24.07.2005 21:12, Ciprian a écrit : > while((testTime-initialTime) < 30) > { > time(&testTime); > test /= 10; > test *= 10; > test += 10; > test -= 10; > > counter ++; > > }
> In windows were performed about 300 millions cycles, > while in Linux about 10 millions. This test was run on > Fedora 4 and Suse 9.2 as Linux machines, and Windows > XP Pro with VS .Net 2003 on the MS side. My CPU is a > P4 @3GHz HT 800MHz bus.
Hi,
This test gives you the price of the time function on each OS since the 4 arithmetical operations are shorter to compute (several cycles against tons of cycles). It appears that the time function costs about 3 us on Linux against 0.1 us on Windows. This function is probably very OS-dependant since it depends on how the kernel handles timing. You can't compare anything as small as these arithmetical operations like this. Using rdtsc would be much better.
Anyway, if you just want to measure the cost of arithmetic operations, there shouldn't be any difference in the results between Linux and Windows (with a safe timing method).
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