Messages in this thread Patch in this message | | | Date | Tue, 29 Jul 2003 12:05:55 -0400 (EDT) | Subject | Re: [REPOST] "apm: suspend: Unable to enter requested state" after 2.5.31 (incl. 2.6.0testX) | From | "Charles Lepple" <> |
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Alan Cox said: > Does it work any better if you change the 0x0, 0x00409200 to > > 0x00109300, 0x00409200 ?
Is this what you're referring to?
--- arch/i386/kernel/apm.c.orig 2003-07-27 12:57:00.000000000 -0400 +++ arch/i386/kernel/apm.c 2003-07-29 11:18:52.000000000 -0400 @@ -424,7 +424,7 @@ static DECLARE_WAIT_QUEUE_HEAD(apm_suspend_waitqueue); static struct apm_user * user_list; static spinlock_t user_list_lock = SPIN_LOCK_UNLOCKED; -static struct desc_struct bad_bios_desc = { 0, 0x00409200 }; +static struct desc_struct bad_bios_desc = { 0x00109300, 0x00409200 }; static char driver_version[] = "1.16ac"; /* no spaces */
I tried this on top of 2.6.0-test2, and it didn't work. Where does the first number in that initializer come from?
In case it has something to do with the APM entry points: apm: entry fcd4:0 cseg16 f000 dseg 9f80 [...]
thanks,
-- Charles Lepple <clepple@ghz.cc> http://www.ghz.cc/charles/ - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
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